Answer to Question #166000 in General Chemistry for cilene liscano

Question

what is the LR when 10mol iron sulfide reacts 200g oxygen FeS2+o2

Answer 1

The chemical reaction is as follows:

4 FeS₂ + 11 O₂ = 2 Fe₂O₃ + 8 SO₂

From here:

n(FeS₂) = 10 mol / 4 = 2.5 mol

n(O₂) = m(O₂) / (11 × Mr[O₂]) = 200 g / (11 × 32) = 0.57 mol

Since, the number of moles of O₂ is lower than the number of moles of FeS₂, oxygen is a limiting reactant.

Answer: Oxygen (O₂)