Answer to Question #165985 in General Chemistry for Tiara Richardson

Question

An iron cube has the volume of 4.76 cm^3. If iron has a density of 7.680 x 10^3 kg/m^3, how many moles are in the cube?

Answer 1

We have given,

Volume of Iron Cube = $4.76cm^{3}$ = $4.76\times10^{-3}m^{3}$

Density = $7.680\times10^{3}kg/m^{3}$

We know,

Density =$\dfrac{Mass}{Volume}$

$7.680\times10^{3} = \dfrac{Mass}{4.76\times10^{-3}}$

Mass = $36.55kg$

Hence, number of moles in the cube= $\dfrac{Mass}{Molar Mass}$

= $\dfrac{36.55}{55.84}$

= $0.6545 moles$