Question

At what temperature will 0.7 mole of chlorine exert a pressure of 1.18 atm at a volume of 0.75L?

Answer 1

n = 0.7 mole

P = 1.18 atm

V = 0.75L

R = 0.082057 L atm/mol.K

PV = nRT

$T = \dfrac{PV}{nR} = \dfrac{1.18 × 0.75}{0.7×0.082057} =$ 15.4K