At what temperature will 0.7 mole of chlorine exert a pressure of 1.18 atm at a volume of 0.75L?
n = 0.7 mole
P = 1.18 atm
V = 0.75L
R = 0.082057 L atm/mol.K
PV = nRT
"T = \\dfrac{PV}{nR} = \\dfrac{1.18 \u00d7 0.75}{0.7\u00d70.082057} =" 15.4K
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