Answer to Question #165636 in General Chemistry for Maddy Brown

Question #165636

A) How many moles of ammonium ions are in 0.732 g of ammonium carbonate?

B) What is the mass, in grams, of 0.0331 mol of iron(III) phosphate?

C) What is the mass, in grams, of 1.70 x10^23 molecules of aspirin, C9H8O4?

D) What is the molar mass of a particular compound of 0.086 mol weighs 6.98 g?


1
Expert's answer
2021-02-25T03:12:52-0500

Solution:


A) "moles=\\dfrac{m}{M}=\\dfrac{0.792g}{96(\\frac{g}{mole})}=8.25*10^{-3}moles"


B) "mass=moles*M=0.0331 \\;moles*\\; 151\\;\\frac{g}{moles}=4.9981g"


C) "\\dfrac{molecules}{N_A}=\\dfrac{1.7*10^{23}}{6.02*10^{23}}=0.282moles"


"mass=moles*M=0.282\\;moles*\\;180\\frac{g}{moles}=50.76g"


D) "M=\\dfrac{mass}{moles}=\\dfrac{6.98g}{0.086moles}=81.12 \\;(\\frac{g}{moles})"


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS