Calculate the mass of ammonia required to produce 3.01x10^23 Molecules of nitrogen according to the following equation 4NH3+3O2➡️2N2+6H2O
n(N2) = 3.01x10^23/6.02x10^23 = 0.5 mol
n(NH3) = 0.5*2 = 1 mol
m(NH3) = 1mol*17g/mol = 17 g
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