How many grams of sodium hydroxide (NaOH) are needed to prepare a 0.700 molal solution using 700.0 grams water?
Molar mass of NaOH = 40 g
Molality = 0.700 mol/kg
Mass of water = 700.0 g =0.700 kg
Mass of NaOH = 0.700 x 0.700 x 40
= 19.6 g
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