Question #164591

A metalic element X with RAM x form two oxide p and q . Oxide p contain 70% of X and q contain 72.4% of X. If the first oxide has the formula X2O3 what is the formula of the second oxide?

Expert's answer

Formula for first oxide = X_{2}O_{3}

Mass of metal X = x

% of metal in X_{2}O_{3} = "\\frac{2x}{2x+48}" × 100

But as given % = 70%

x = 56

In second oxide

Metal given 72.4% , so oxygen will be 27.6 %

So the ratio is :

Metal : oxide

"\\frac{72.4}{56}" = "\\frac{27.6}{16}" =1.29:1.72 = 3:4

So formula for second oxide = X_{3}O_{4} 4

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