Answer to Question #164570 in General Chemistry for Ming

Question

Given the reaction below, what is the mass of the products formed when 30 liters of CO gas is used at

STP?

I 2 O 5 (s) + CO(g) I 2 (s) + CO 2 (g)

Answer 1

I₂O₅(s) + 5CO(g) → I₂(s) + 5CO₂(g)

1 mole of any gas occupies 22.4 L at STP.

Proportion:

1 mol – 22.4 L

x – 30 L

$x = \frac{1 \times 30}{22.4}=1.34 \;mol$

n(CO) = 1.34 mol

According to the reaction:

n(I₂) $= \frac{n(CO)}{5} = \frac{1.34}{5} = 0.268 \;mol$

$m = n \times M$

M(I₂) = 253.8 g/mol

m(I₂) $= 0.268 \times 253.8 = 68.02 \;g$

According to the reaction:

n(CO₂) = n(CO) = 1.34 mol

M(CO₂) = 44.01 g/mol

m(CO₂) $= 44.01 \times 1.34 = 58.97 \;g$