Answer to Question #163994 in General Chemistry for Amber Clifton

Question #163994

An acid-base titration was performed. It took 27.45 mL of the base, KOH, to titrate 3.115 g HBr, the acid. What was the Molarity of the KOH?

1
Expert's answer
2021-02-16T07:48:41-0500
"n(HBr)=3.115\/81=0.0385 mol"

According to the reaction n(HBr)=n(KOH)=0.038 mol

"C(KOH)=n\/V=0.0385\/0.02745=1.4M"



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