Answer to Question #163341 in General Chemistry for mike

Question #163341

Sodium iodate reacts with sodium sulfite according to the equation :

NaIO3    +    3Na2SO3     →     3Na2SO4    +    NaI

a). In this reaction, which substance is the oxidising agent? Why?

b). How many grams of NaIO3 are needed to react with 5.00g of Na2SO3?


1
Expert's answer
2021-02-15T03:08:51-0500

a. NaIO3 is the Oxidizing agent.

The reason is that the Oxidation number of Iodine changes from +5 in NaIO3 to -1 in NaI. This shows that the compound itself undergoes reduction (as an oxidizing agent)


b. Molar mass of NaIO3= 198g/mol

Molar mass of Na2SO3= 86g/mol

From the equation

3(86)g of Na2SO3 reacts with 198g of NaIO3

5.00g of Na2SO3 will react with

198 x 5.00/258 = 3.84g of NaIO3

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS