Answer to Question #162805 in General Chemistry for Nally

General Chemistry

Question #162805

How many mL of 10.8M HCl are required to make 150.0 mL of 3.00M acid?

Expert's answer

Let the volume to be determined be x

X × 10.8 = 150 ×3

X = 150 ×3 /10.8

X= 41.67mL

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