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Answer to Question #162774 in General Chemistry for Bella winter

Question #162774

What volume of 0.300 M calcium chloride contains 3.50g of calcium chloride


1
Expert's answer
2021-02-11T04:49:59-0500

3.50g CaCl2 × (1mol CaCl2 /110.98g CaCl2)

= 0.0315 moles

Molarity = no. of moles / volume

0.300 = 0.0315 / volume

Volume = 0.0315/0.300

Volume = 0.105 L


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