Answer to Question #162463 in General Chemistry for Ava

Question #162463

The gas in a 250.0 mL piston experiences a change in pressure from 1.00 atm to 2.80 atm. What is the new volume (in mL) assuming the moles of gas and temperature are held constant?

Expert's answer

P₁V₁=P₀V₀

V₁=P₀V₀/P₁

V₁=1.00*250.0/2.80=89.28(ml)

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