Answer to Question #162156 in General Chemistry for Cecilia

Question

Professor Jones created a fictitious unit called the dulfinch (dulfin). If 1.75 dulfin = 1.5x10^-2 m, then 88.8 dulfin² is equivalent to _______ mm².  

Answer 1

1.75 dulfin = 1.5×10^-2 m

1 dulfin = (1.5×10^-2)/1.75 m

1dulfin² = ($\frac{1.5×10^-²}{1.75}m$ )²

1 dulfin² = (0.85714×10^-2m)²

1 dulfin² = 0.734688×10^-4 mm²

88.8 dulfin² = 88×0.734688×10^-4 mm²

88.8 dulfin² = 65.24×10^-4 mm²