Calculate the energy of an electron in the n = 7 level of a hydrogen atom.
E = "\\frac{13.6}{n^2}" × eV
E = energy , n = 7 , eV = 1.6×10-19
E = "\\frac{13.6}{7^2}" × 1.6×10-19 J
E = "\\frac{13.6}{49}" × 1.6×10-19 J
E = 0.444×10-19 J
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