Question

If you react 11.45 grams of Cu, how many grams of NO are produced?

 

3Cu + 8HNO₃ → 3Cu(NO₃)₂+ 2NO + 4H₂O

Answer 1

11.45 g Cu ×$\frac{1moleCu}{63.546gCu}$ = 0.1801 mole Cu

0.1801 mole Cu × $\frac{2moleNO}{3moleCu}$ × $\frac{30.01gNO}{1moleNO}$

= 3.60 g NO