If you react 11.45 grams of Cu, how many grams of NO are produced?
3Cu + 8HNO3 → 3Cu(NO3)2+ 2NO + 4H2O
11.45 g Cu ×"\\frac{1moleCu}{63.546gCu}" = 0.1801 mole Cu
0.1801 mole Cu × "\\frac{2moleNO}{3moleCu}" × "\\frac{30.01gNO}{1moleNO}"
= 3.60 g NO
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