Question #161478

**Using the equation:**

** **

** C3H8Â +Â 5O2Â â†’Â 3CO2Â +Â 4H2O**

**1. Calculate the moles of O2 needed to make 1.35 mol H2O.**

**2. Calculate the moles of C3H8 needed to make 13.4 mol CO2.**

**3. Calculate the moles of CO2 produced when 0.458 mol C3H8 reacts.**

**4.Â Calculate the the moles of H2O produced from 11.2 mol O2**

**5. Calculate the moles of CO2 produced when 3.86 mol O2 reacts.Â **

**6.Â Calculate the moles of H2O produced when 9.54 mol C3H8 reacts.**

**7. Calculate the moles of C3H8 needed to produce 35.6 mol H2O.**

**8.Â Calculate the moles of O2 reacted when 3.57 mol of C3H8 combusts.**

**9.Â Calculate the moles of H2O produced when 2.68 mol CO2 is made.**

**10. Calculate the moles of CO2 produced when 0.876 mol C3H8 reacts.Â **

Expert's answer

In all these cases the proportions including reaction coefficients should be used.

1. n(O2)=5*1.35/4=1.6875(mol)

2. n(C3H8)=1*13.4/3=4.47(mol)

3. n(CO2)=3*0.458/1=1.374(mol)

4. n(H2O)=11.2*4/5=8.96(mol)

5. n(CO2)=3*3.86/5=2.316(mol)

6. n(H2O)=9.54*4/1=38.16(mol)

7. n(C3H8)=1*35.6/4=8.9(mol)

8. n(O2)=5*3.57/1=17.85(mol)

9. n(H2O)=4*2.68/3=3.57(mol)

10. n(CO2)=3*0.876/1=2.628(mol)

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