To burn 456 grams of nonane (C9H20), how many liters of oxygen are needed?
C9H20+14O2=9CO2+10H20
"n(C9H20)=\\frac{m}{M}=\\frac{456}{128.259}=3.56"
"\\frac{3.56}{1}=\\frac{x}{14}"
x=49.77
"V(O2)=Vm\\times n=22.4\\times49.77=1114.94" L
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