At what pressure will a sample of He (g) have a
density of 0.112 g/L at 27°C?
PM = "\\rho" RT
M (molar mass of helium) = 4
R = 0.0821
T = 273+27 = 300K
"\\rho" = 0.112g/L
P×4 = 0.112×0.0821×300
P = 0.68964 atm
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