Question

Molybdenum forms body-centered cubic crystals and at 20 oC the density is 10.3

g/mL. Calculate the distance between the centers of the nearest molybdenum

atoms. 

Answer 1

In bcc no of atoms=2

density=10.3g/ml

molar mass of molybdenum=95.95g/mol

now

d=$\tfrac{ZM}{a^3N_A}$

10.3=$\tfrac{2*95.95}{a^3*6*10^23}$

a=3.16*10$^-8$ cm