How many moles of H₂0 will be required to make 19.2 moles of O₂?
As shown in the picture above,
according to the Stoichiometry ,
nH2OnO2=x19.2=21x=38.4mol\dfrac{n_{H_{2}O}}{n_{O_{2}}} = \dfrac{x}{19.2} = \dfrac{2}{1} \\ \\ x = 38 . 4 molnO2nH2O=19.2x=12x=38.4mol
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