Answer to Question #156024 in General Chemistry for Lia Rodriguez

Question

If we have a sodium chloride solution that is 0.14 M. (Molar mass 585 g / mol. We can deduce the following data: 

A. For each kilogram of solution there are 0.14 moles of solute

B. For every kilogram of solvent there are 0.14 moles of solute

 C. For every kilogram of solvent there are 8.19 grams of solute 

D. For each liter of solution there are 8.19 grams of sodium chloride

E. For each liter of solution there are 58.5 grams of sodium chloride

Answer 1

molarity of solution = 0.14M = 0.14 mol/dm³.

This means that for every 1L of the solution, there are 0.14 moles of sodium chloride

1L = 0.14 moles

1L = 0.14 moles × 58.5 g/mol

1L of solution = 8.19g of Sodium Chloride.

Therefore, D should be correct.