Answer to Question #145993 in General Chemistry for Loz

Question #145993
A solution is made by mixing 500.0ml of 0.12M NaOH soulution with 500mL of 0.1M Mg(NO3)2

Ksp for Mg =1.8 x10^-11

What will Mg and Oh^- be after mixing?
1
Expert's answer
2020-11-23T06:58:16-0500

500.0ml of 0.12M NaOH 


500mL of 0.1M Mg(NO3)2


Ksp for Mg =1.8 x10^-11


500 ml = 0.12m


1000ml = ? ((1000)(0.12))/ (500)


= 0.24moles


500ml = 0.1m


1000ml = ((1000)(0.1))/500


= 0.2 moles


Therefore


(0.2)(0.24)(1.8 x10^-11)


= 8.64-13



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