Answer to Question #135802 in General Chemistry for Kellie

Question

To neutralize 25.0mL of a 0.100M solution of HCL requires 40.5 mL of a solution of NaOH. Determine the concentration of the NaOH solution in units of molarity

Answer 1

C₁V₁=C₂V₂

at the equivalent point

C(NaOH)=(C(HCl)*V(HCl))/V(NaOH)

C(NaOH) = (25 mL * 0.1M)/40.5mL=0.062M