Answer to Question #135740 in General Chemistry for Austin

Question #135740

How many moles of CaCO3 are formed from 35.08g of CaO


1
Expert's answer
2020-10-04T09:22:08-0400

CaCO3 ---- CaO +CO2


1 mole of CaCO3----100grams

100g of CaCO3-- 56 g of CaO

--- 35.08g

(35.08×100)÷56=62.64 grams of caco3

1 mole of caco3 =100 grams

? =62.64 grams

(62.64×1)÷ 100= 0.63 moles

=0.63 moles.


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