Question #134917
1. Compute for the pH of 0.415 M HCl acid.
1
Expert's answer
2020-10-06T09:16:22-0400
pH=−logc(H+)=−logc(HCl)pH = -logc(H^+)= -logc(HCl)

pH=10−0.415=0.385pH = 10^{-0.415} = 0.385


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