The dissociation of Pbl, is as follows:
Pbl2 gives Pb2+ + 2I-
Ksp of Pbl2 =7.1x10-9
The expression for the K of the reaction is as follows:
Construct an ICE table for the reaction.
Pbl2 gives Pb+2+ 2I-
Initial: 0 0.1
Change +x +2x
Equilibrium: x (0.1+2x)
Substitute these values in the expression as follows:
Solve for x
x= 7.1x10-7 M
Therefore, the molar solubility of Pbl2 in KI is 7.1x10-7 M.
The molar solubility of Pbl2 is 1.22x10-3 M