Answer to Question #133447 in General Chemistry for hi

Question #133447
Show how to calculate the molar solubility of PbI2 in 0.1M KI (aq)? Ksp=7.1x10-9
1
Expert's answer
2020-09-21T06:32:22-0400

The dissociation of Pbl, is as follows:


Pbl2 gives Pb2+ + 2I-


Ksp of Pbl2 =7.1x10-9


The expression for the K of the reaction is as follows:


Construct an ICE table for the reaction.


Pbl2 gives Pb+2+ 2I-


Initial: 0 0.1


Change +x +2x




Equilibrium: x (0.1+2x)


Substitute these values in the expression as follows:


Ksp= (Pb+2)(I-)2

7.1x10 =(x){0.1+2x)2


Solve for x


x= 7.1x10-7 M


Therefore, the molar solubility of Pbl2 in KI is 7.1x10-7 M.


The molar solubility of Pbl2 is 1.22x10-3 M




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