A sample of limestone, CaCO3 was sealed inside a strong glass tube. The mass of the tube and limestone was found to be 156.4g. The tube was then heated over a Bunsen burner, causing the formation of some quicklime, CaO and carbon dioxide gas?
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Expert's answer
2020-07-13T07:21:38-0400
When CaCO3 is strongly heated, it undergoes thermal decomposition to form CaO and CO2
The equation for the reaction is as follows;
CaCO3(s)→CaO(s)+CO2(aq)
The mass of the products after the reaction is not affected by the reaction hence the products mass remains at 156.4g after the reaction.
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