Answer to Question #124500 in General Chemistry for Evan Arvanitis

Question

In the laboratory a student finds that it takes 56.4 Joules to increase the temperature of 11.0 grams of solid chromium from 23.7 to 35.9 degrees Celsius. The specific heat of chromium calculated from her data is ____ j/gC

Answer 1

In the laboratory a student finds that it takes 56.4 Joules to increase the temperature of 11.0 grams of solid chromium from 23.7 to 35.9 degrees Celsius. The specific heat of chromium calculated from her data is 0.420 J/g°C

C = Q / (m×T )         C= Specific heat, Energy(Q)= 56.4 J, Mass(m)= 11 g,

C = 56.4 /(11.0×12.2) J/(g×°C)                Change of temperature (T) = (35.9-23.7)°C

= 0.420 J/(g×°C) (Answer)                                                                =12.2°C