Question #124382
A metal cube with a mass of 55grams at temperature of 85°C is immersed in 150grams of water at temperature of 20°C. The metal and water then reach a final temperature of 23oC. How much heat does the water gain?

Specific heat of water, which is 4.184 J/gC.
1
Expert's answer
2020-06-29T07:45:23-0400

heat loss by metal = heat gained by water

m1C(∆T1) = m2C(∆T2)

heat gained by water= m2C(∆T2)

= 150*4.184*( 296-293)

=150*4.184*3

= 1882.8 joules


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Comments

Assignment Expert
02.06.21, 14:06

Dear Abigail Torres 20°C = 293 K 23°C = 296 K


Abigail Torres
02.06.21, 04:06

How did you get 296-293?

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