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Answer to Question #118028 in General Chemistry for Crizzia Paula Lobrido
Question #118028
The equilibrium constant for the formation of calcium carbonate from the ions in solution is 2.2x108 according to the reaction:
Ca2+(aq) + CO32-(aq) ⇄ CaCO3(s) K=2.2x108
What is the equilibrium constant of
2CaCO3(s) ⇄ 2Ca2+(aq) + 2CO32-(aq) K=?
Ca2+(aq) + CO32-(aq) ⇄ CaCO3(s) K=2.2x108
What is the equilibrium constant of
2CaCO3(s) ⇄ 2Ca2+(aq) + 2CO32-(aq) K=?
Expert's answer
K=1/2.2x108
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