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# Answer to Question #46586 in Biology for Katelyn

Question #46586
If the homozygous recessive genotype makes of 9% of the population and the heterozygous genotype makes up 42% of the population, what is the frequency of the dominant allele in that population?
1
2014-10-22T09:41:39-0400

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24.09.14, 12:29

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24.09.14, 07:41

allele not genotype. (genotype % below) out of 100 people 9% homo reces = 9 people rr 42% hetero = 42 people w/ Rr ?% homo dom?= ? people w/ RR Genotype = 2 alleles. allele frequency = # of allele / all possble alleles at that locus 9 aa = so two aa per person. 2x 9 = 18 total a alleles 42 Aa = one a per person AND one A per person 42 a and 42 A 42% + 9% + X% = 1. (hardy w.) so AA = 49%. sample = 100 then 49 people have AA. 49 people AA = two A per person. 49 x 2 = 98 A total. + 42 = 140/200 ales