Two strains of E. coli, A and B, are inoculated into a chemostat in equal
proportions. After one generation, the frequency of strain B is 20%. Calculate the
fitness of strain B relative to strain A.
The genotype with the highest reproductive ability is given a fitness value of 1.0. The fitness values of the other genotypes are assigned values relative to this 1.0 value. In our case fitness of strain A is 1.0 and fitness of strain B is 0.2. It means that all bacteria of strain A will survive, and only 20 percent of strain B bacteria will survive.
Motivating students to do something requires creativity, as not one student thinks like another. One thing that students usually looked…
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