Answer to Question #149209 in Human Anatomy and Physiology for K

Question

What’s the water potential of a sucrose solution in an open container at.5m and at 27 degrees

Answer 1

The water potential of a solute is given by the formula;

Water potential (Ψw)= Solute potential (Ψs) + Pressure potential (Ψp)

Solute potential is given by; ΨS = -icRT, which is equivalent to -12.465 or -12.47.

The water potential of the solute (sucrose) will be -12.47 since the pressure potential of an open container is 0.