# Answer to Question #79771 in Genetics for Arfa

Question #79771

In a random mating population of 20000, 16800 individuals are the dominant then how many individuals will be homozygous?

Expert's answer

The number of individuals with recessive phenotype is 20000 - 16800 = 3200.

Their proportion in the population is 3200 / 20000 = 0.16

As individuals with recessive phenotype can have aa genotype only, the frequency of recessive allele is sqrt (0.16)=0.4

The frequency of dominant allele is 1 - 0.4=0.6

The frequency of homozygous individuals with dominant phenotype is 0.6^2 = 0.36

The number of such individuals is 0.36 * 20000 = 7200

Their proportion in the population is 3200 / 20000 = 0.16

As individuals with recessive phenotype can have aa genotype only, the frequency of recessive allele is sqrt (0.16)=0.4

The frequency of dominant allele is 1 - 0.4=0.6

The frequency of homozygous individuals with dominant phenotype is 0.6^2 = 0.36

The number of such individuals is 0.36 * 20000 = 7200

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment