Answer to Question #77276 in Genetics for Sarah
The frequency of red-sides animals is equal to their probability, and for this population comprises 250 / (250+750) = 0.25.
Let q is the probability of recessive allele. Then, q^2 = 0.25, and q =0.5
Let p is the probability of dominant allele. Then, p=1-q, p=0.5
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