Question #67452

Calculate the frequency of the two alleles showing incomplete dominance. Phenotype and population... hom fast=976 hom slow =58 heterozygous 316.

Expert's answer

The total number of individuals in population is 976 + 58 + 316 = 1350.

Frequency of allele for hom fast: (2*976 + 316)/2*1350 = 0.84

Frequency of allele for hom slow: 1-0.84 = 0.16

Frequency of allele for hom fast: (2*976 + 316)/2*1350 = 0.84

Frequency of allele for hom slow: 1-0.84 = 0.16

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