Answer to Question #107222 in Genetics for Chelsy Sampson

Question #107222
The following is a hypothetical situation. Assume that the presence and color of hair in a breed of dog is controlled by 2 separate genes. The first gene
controls the presence or absence of hair. Individuals who are homozygous recessive have hair, while those with at least one dominant allele are naked/hairless.
The second gene for hair color produces either blond, brown, or black hair, with those that are homozygous for one allele having blond hair, those who are
homozygous for the other allele having black hair, and the heterozygous individuals being brown-haired.
Show the offspring be for the following cross:
A hairless male is crossed with a brown-haired female. The male had a black-haired mother and a hairless father with blond-haired genes
Expert's answer

Let the gene which controls the presence or absence of hair be A or a, and the gene for hair color be B or b. Let the blond allele be b and the black allele be B. * unknown alelle.

Parents of a male: A*bb x **BB

A*Bb x **Bb

We don’t have enough information of genes that control hair presence, so we will get the following results:

2 A*BB – bald and black

4 A*Bb – bald and brown

2 A*bb – bald and blond

2 **BB – hair or bald and black

4 **Bb – hair of bald and brown

2 **bb – hair or bald and blond

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