There is 36µg of ampicillin in the sample. Therefore, 36 to 360µg of enzyme ( representing 14.4 to 144 Units) are required. The enzyme molecular weight is 29kDa and assuming that the preparation is pure. The final concentration of ampicillin in the sample is (36µg/349.406)/200µL=516.16µM. So, the concentration of enzyme needed for the 1:1 ratio and 5.16mM for the 1:10 ratio corresponds to 0.103µmol and 1.03µmol of enzyme in the 200µL sample, respectively. If the molecular weight is 29kDa then; 0.103*10-6*29000=2.987mg and 29.87mg respectively will be required.