Answer to Question #9666 in Biochemistry for Meri
HOBr → H+ + OBr–
a. Write the equation you would use to calculate the Ka of this reaction.
b. If [H+] at equilibrium is 9.1 × 10–6, what is the Ka of the reaction, given a final HOBr concentration
of 0.33 M?
b. HOBr → H+ + OBr–
Ka=[H+]^2 /[HOBr]=(9.1 × 10–6)^2 /0.33 =2,51*10^-10
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