What will be the probable number of type of genotypes in a cross AABBCC×aabbcc in F2 ?
a)27 b)64 c)8 d)81
Your F1 generation will be doubly heterozygous: AaBbCc, so crossing two of these individuals will give us how many genotypic combinations? How many genotypes can be produced in the offspring at just locus “A”? 3: AA, Aa, and aa. How many at just the “B” locus? 3: BB, Bb, and bb. The same is true for the remaining locus C. Multiply the number of genotypes at each locus to get the total number of genotypes for all of them combined: 3 x 3 x 3 = 27 possible genotypes. a) 27