Millimoles of CH3COOH=0.1×10=1.0
Millimoles of CH3COONa=0.1×100=10
From, Henderson Hasselbalch equation,
pH=ppKa log "\\frac{conjugate base}{acid}"
= 4.24 + log "\\frac{20}{1}"
4.24 + 1.3
= 4.54
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