Calculate the amount of fructose 6 phosphate formed from glucose 6 phosphate in a 10 milliliter incubation system if 0.5M G6P is incubated overnite at 25oC and the equilibrium constant is 0.67.
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Expert's answer
2011-05-18T04:51:41-0400
Reaction: Glucose-6-P& ----> Fructose-6-P 0,5 M& & 0 x& x 0,5 - x& x
For the following reaction expression of the equilibrium constant is:
K=0.67=& x/(0.5-x) X = 0.2 n (Fructose-6-P) = 0.2 M * 0.01 L = 2 mmol
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