"pH=pka+log(A)\/(HA)"
1)convert the ml into litres.we will get 0.002l of buffer and 0.008l.The difference will be 0.192
pH=4.0+log(0.008/0.192)
pH=4.0- 1.380=2.62
2)pH=4.0+log(0.008/0.192)
=2.62
3) pH=4.7+log(0.002/0.048)
=4.7+1.38=6.08
4) pH=3.3+log (0.15/0.13)
=3.3+0.81=4.11
5) pH=4.7+log (0.002/0.048)
=4.7-1.38=3.32
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