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Answer to Question #35156 in Mechanics | Relativity for Kristen Woods
Question #35156
Use the 5-step method and be sure to include units where appropriate. Round your answers to the correct number of significant digits.
Adjust the density formula and solve the problems below:
Pure gold has a density of 119.32 g/cm3. How large would a piece of gold be if it had a mass of 3118.97 g?
Adjust the density formula and solve the problems below:
Pure gold has a density of 119.32 g/cm3. How large would a piece of gold be if it had a mass of 3118.97 g?
Expert's answer
The density formula is
ρ(g/cm^3) = (m(g))/(Vcm^3))
According to this formula the volume of the metal is
V(cm^3) = □((m(g))/(ρ(g/cm^3))
V(cm^3) = 3118.97/119.32 = 26.1 cm^3
Answer: V = 26.140 cm^3
ρ(g/cm^3) = (m(g))/(Vcm^3))
According to this formula the volume of the metal is
V(cm^3) = □((m(g))/(ρ(g/cm^3))
V(cm^3) = 3118.97/119.32 = 26.1 cm^3
Answer: V = 26.140 cm^3
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