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Answer on Mechanics  Kinematics  Dynamics Question for Eric
Question #1045
I was wondering if i could get help with this problem:
Two billiard balls of equal mass undergo a headon collision. The speed of ball 1 was initially 6.00 m/s to the right, and that of ball 2 was 8.00 m/s in the opposite direction (to the left). After they bounce off of each other the speed of ball 1 is 8.00 m/s.
What is the speed of ball 2 after the collision?
Two billiard balls of equal mass undergo a headon collision. The speed of ball 1 was initially 6.00 m/s to the right, and that of ball 2 was 8.00 m/s in the opposite direction (to the left). After they bounce off of each other the speed of ball 1 is 8.00 m/s.
What is the speed of ball 2 after the collision?
Expert's answer
Answer
According to the Momentum Concervation Law for a headon collision:m_{1}v_{1} + m_{2}v_{2} = m_{1}v_{1}' + m_{2}v_{2}';
as m_{1} = m_{2},
v_{1} +v_{2} = v_{1}' + v_{2}';We chose the direction to the right as positive.
6  8 = 8 + V;
V = 6  the second ball would have the speed on 6 m/s to the right.
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