UNIX/Linux Programming Answers

Create a shell script which prints the line contents when the line number is divisible by 3 from an input file. Assume the first line is line 1. At the end of the script, if the total number of lines divisible by 3 is greater than 10, print “big”. Otherwise, print “small”.

I need help in answering this question. so far this is what I have

echo $1

file=$1

awk 'NR%2==0' $file

count=$(wc -l $file | grep -o "^[0-9]")

if [ $count -gt 20 ]
then
printf "\nbig\n"
else
printf "\nsmall\n"
fi

Create a shell script which prints the line contents when the line number is divisible by 3 from an input file. Assume the first line is line 1. At the end of the script, if the total number of lines divisible by 3 is greater than 10, print “big”. Otherwise, print “small”.

I need help in answering this question. so far this is what I have

echo $1

file=$1

awk 'NR%2==0' $file

count=$(wc -l $file | grep -o "^[0-9]")

if [ $count -gt 20 ]
then
printf "\nbig\n"
else
printf "\nsmall\n"
fi

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