67 058
Assignments Done
99,3%
Successfully Done
In November 2018

Answer to Question #2724 in Vector Calculus for saman khan

Question #2724
Find the angles which the vector 3i-6j+3k makes with the coordinate axes.
Expert's answer
The module of the vector is √(32 + 62 + 32) = √54
As a b = |a||b| cos α,
we can obtain
the angle with i - axis (1,0,0):
cos α1 = (3*1 -6*0 + 3*0)/√54*1 = 0.41, α1 = 66 degrees

the angle with j - axis (0,1,0):
cos α2 = (3*0 -6*1 + 3*0)/√54*1 = - 0.82 α2 = 145 degrees

the angle with k- axis (0,0,1):
cos α3 = (3*0 -6*0 + 3*1)/√54*1 = 0.41 α3 = 66 degrees

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

Submit
Privacy policy Terms and Conditions