Answer to Question #7979 in Linear Algebra for Muhammad Imran Qureshi
we find the equation of the plane W spanned by the vectors v=(1,1,1) and
The normal vector, n=(nx,ny,nz), to this plane is the
This vector has the following
nx = det 1 1 = 3-2 = 1
= det 1 1 = 1-3 = -2
nz = det 1 1 = 2-1 =
Thus n=(1,-2,1) and the equation of the plane
Thus u satisfies the equation:
Moreover, since u belongs to U, we have that c=0.
a-2b=0 => a=2b.
Hence we can take u=(2,1,0).
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