Answer on Question #61931 – Math – Linear Algebra
Question
Show that an orthogonal map of the plane is either a reflection, or a rotation.
Solution
If T:R2→R2 is an orthogonal linear operator, then the standard matrix for T can be expressed in the form
Rθ=[cosθsinθ−sinθcosθ]
(Rθ rotates vectors by θ radians, counterclockwise)
or
H2θ=[cosθsinθsinθ−cosθ].
The determinant can be used to distinguish between the two cases:
detRθ=cos2θ+sin2θ=1detH2θ=−(cos2θ+sin2θ)=−1.
Thus, a 2×2 orthogonal matrix represents a rotation about the origin if det=1 and a reflection about a line through the origin if det=−1. This sentence may be a definition of an orthogonal map of plane. If the definition of 2×2 matrix is ATA=I, where I is an identity matrix, then the determinant of an orthogonal matrix is equal to 1 or −1, because using properties of determinants and equality ATA=I, obtain det(A)=det(AT) and
1=det(I)=det(ATA)=det(AT)det(A)=(det(A))2, hence det(A)=1 or det(A)=−1.
Lemma. Every orthogonal transformation of the Euclidean plane is a reflection or a rotation.
We consider the effect of an orthogonal transformation T on the two vectors α=(1,0) and
β=(0,1). The orthogonality of T forces T(α) and T(β) also to be of unit length and orthogonal to each other. Let θ and θ^ be the counter-clockwise angles formed by T(α) and T(β) with the x-axis. Then θ^=θ±2π. In the case θ^=θ+2π, T is a rotation through angle θ. In the case θ^=θ−2π, T is a reflection through the dashed line forming an angle of 2θ with the x-axis. In the pictures we have


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